11011+1100+10100,1+1011

asked by guest
on Nov 16, 2024 at 5:01 am



MathBot Answer:

The sum of \(11011 + 1100 + 10100\) and \(1 + 1011\) is:

\[\begin{aligned}&=\left(11011 + 1100 + 10100\right) + \left(1 + 1011\right) \\\\ &= 23223 \\\\\end{aligned}\]

The difference of \(11011 + 1100 + 10100\) and \(1 + 1011\) is:

\[\begin{aligned}&=\left(11011 + 1100 + 10100\right) - \left(1 + 1011\right) \\\\ &= 21199 \\\\\end{aligned}\]

The product of \(11011 + 1100 + 10100\) and \(1 + 1011\) is:

\[\begin{aligned}&=\left(11011 + 1100 + 10100\right) \cdot \left(1 + 1011\right) \\\\ &= \left(1 + 1011\right) \left(1100 + 10100 + 11011\right) \\\\ &= 22477532 \\\\\end{aligned}\]

The quotient of \(11011 + 1100 + 10100\) and \(1 + 1011\) is:

\[\begin{aligned}&= \frac{\left(11011 + 1100 + 10100\right)}{\left(1 + 1011\right)} \\\\ &= \frac{1100 + 10100 + 11011}{1 + 1011} \\\\ &= \frac{22211}{1012} \\\\\end{aligned}\]

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