expand and fully simplify 3(r-1)+2(3r+5)
asked by guest on Mar 30, 2025 at 6:53 am
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MathBot Answer:
3(r−1)+2(3r+5)=9r+7 3 \left(r - 1\right) + 2 \left(3 r + 5\right) = 9 r + 7 3(r−1)+2(3r+5)=9r+7
3(r−1)+2⋅(3r+5)=2⋅(3r+5)+3r−3=3r−3+6r+10=9r+7\begin{aligned}3 \left(r - 1\right) + 2 \cdot \left(3 r + 5\right)&=2 \cdot \left(3 r + 5\right) + 3 r - 3\\&=3 r - 3 + 6 r + 10\\&=9 r + 7\end{aligned}3(r−1)+2⋅(3r+5)=2⋅(3r+5)+3r−3=3r−3+6r+10=9r+7