integrate e^2xcos2xsin3x dx
asked by guest
on Dec 25, 2024 at 11:56 pm
You asked:
Evaluate the integral:
∫e2xcos(2x)sin(3x)dx
MathBot Answer:
Antiderivative
∫e2xcos(2x)sin(3x)dx=(−2512cos(3x)sin(2x)+2513cos(2x)sin(3x)−53xcos(2x)cos(3x)−52xsin(2x)sin(3x))e2+C
e is Euler's number, a mathematical constant that is approximately 2.71828.