y'=-2*x-y

asked by guest
on Nov 16, 2024 at 9:48 am



You asked:

Investigate the equation: \(y^{\prime} = -2 \cdot x - y\).

MathBot Answer:

\[y{\left(x \right)} = 2 - 2 x + C_{1} e^{- x}\]

\(C_{1}\) is an arbitrary constant.

\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).

+ Submit Question