if a+1/a = 0 then √a+1/√a is equal to?

asked by guest
on Nov 27, 2024 at 9:14 pm



MathBot Answer:

a+1a{i32+i,i+1i}\sqrt{a} + \frac{1}{\sqrt{a}} \in \left\{- i^{\frac{3}{2}} + \sqrt{i}, \sqrt{- i} + \frac{1}{\sqrt{- i}}\right\}


ii is the imaginary unit, defined as i2=1i^2 = -1.

By substituting this value into the expression, we find that: a+1a=1i+i=i32+i\begin{aligned}\sqrt{a} + \frac{1}{\sqrt{a}} &= \frac{1}{\sqrt{i}} + \sqrt{i}\\&= - i^{\frac{3}{2}} + \sqrt{i}\end{aligned}