5x ^ { 2 } +9x-116 \div x-4
asked by guest on Mar 26, 2025 at 8:46 pm
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MathBot Answer:
5x2+9x−116x−4=5x2+9x−4−116x\displaystyle 5 {x}^{2} + 9 x - \frac{116}{x} - 4 = 5 x^{2} + 9 x - 4 - \frac{116}{x} 5x2+9x−x116−4=5x2+9x−4−x116
5x2+9x−116x−4=5x3+9x2−4x−116x5 {x}^{2} + 9 x - \frac{116}{x} - 4 = \frac{5 x^{3} + 9 x^{2} - 4 x - 116}{x}5x2+9x−x116−4=x5x3+9x2−4x−116