(i1)+(i3)-3=0

2(v1)+(i1)-3=0

2(v1)+5(i2)+(i3)=0

(i1)-2(i2)-3(v1)=0

asked by guest
on Jan 15, 2025 at 2:13 pm



Mathbot Says...

I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.