Math Problem Solver

$$35 - 29=6$$

$$\begin{aligned} \overset{\mathtt{{\scriptscriptstyle 2}}}{\cancel{\mathtt{3}}}\overset{\mathtt{{\scriptscriptstyle 15}}}{\cancel{\mathtt{5}}}\\ \mathtt{-\phantom{0}}\mathtt{2}\mathtt{9}\\ \hline \mathtt{0}\mathtt{6} \end{aligned}$$

Borrow $10^{1}$, resulting in $2$ in the $10^{1}$ place, and $15$ in the $10^{0}$ place.

$6$ is the digit in the $10^{0}$ place. $15 \times 10^{0} - 9 \times 10^{0} = 6 \times 10^{0}$.

$0$ is the digit in the $10^{1}$ place. $2 \times 10^{1} - 2 \times 10^{1} = 0 \times 10^{1}$.