1÷((1÷x)+(1÷y)+(1÷z))
asked by guest on Jan 15, 2025 at 10:49 am
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MathBot Answer:
11x+1y+1z=11z+1y+1x\frac{1}{\frac{1}{x} + \frac{1}{y} + \frac{1}{z}} = \frac{1}{\frac{1}{z} + \frac{1}{y} + \frac{1}{x}}x1+y1+z11=z1+y1+x11
11x+1y+1z=xyzxy+xz+yz\frac{1}{\frac{1}{x} + \frac{1}{y} + \frac{1}{z}} = \frac{x y z}{x y + x z + y z}x1+y1+z11=xy+xz+yzxyz