solution set of $x^{2}+X=110$
You asked:
Investigate the equation: \({x}^{2} + X = 110\).
MathBot Answer:
The graph of the equation \({x}^{2} + X = 110\) is a parabola.
The coordinates of its vertex are: \(\left(110, 0\right)\)
The coordinates of its focus are: \(\left(\frac{439}{4}, 0\right)\)
The directrix has equation: \(- 4 X + 441 = 0\).
The parabola has parameterization: \[\begin{aligned}X\left(\theta\right) &= 110 - \theta^{2}\\x\left(\theta\right) &= \theta\end{aligned}\]