Math Problem Solver

\[ \frac{3}{1} + \frac{4}{2} + \frac{12}{3} = 9 \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{3}{1}\), \(\frac{4}{2}\), and \(\frac{12}{3}\) is \(6\). \[ \begin{aligned} \frac{3}{1} + \frac{4}{2} + \frac{12}{3} &= \frac{3 \cdot 6}{1 \cdot 6} + \frac{4 \cdot 3}{2 \cdot 3} + \frac{12 \cdot 2}{3 \cdot 2} \\ &= \frac{18 + 12 + 24}{6} \\ &= \frac{54}{6} \\&= 9 \end{aligned} \]