solve for x in the following equation 4^x[8^[x-1]]=tan45
You asked:
Solve the equation \[{4}^{x} \cdot {8}^{x - 1} = \tan\left( 45 \right)\] for the unknown \(x\).
MathBot Answer:
The solution is: \[x = \log{\left(\left(8 \tan{\left(45 \right)}\right)^{\frac{1}{\log{\left(32 \right)}}} \right)} \approx 0.73915872\]