d/dx (x sinx)
asked by guest on Mar 23, 2025 at 12:33 am
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MathBot Answer:
ddx[xsin(x)]=xcos(x)+sin(x)\frac{d}{dx}\left[x \sin\left( x \right)\right] = x \cos{\left(x \right)} + \sin{\left(x \right)}dxd[xsin(x)]=xcos(x)+sin(x)