e^2 * (x − 1) = (x − 1)^ln(x−1)

asked by guest
on Nov 12, 2024 at 3:55 pm



You asked:

Investigate the equation: \({e}^{2} \cdot \left(x - 1\right) = {\left( x - 1 \right)}^{\ln\left( x - 1 \right)}\).

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