\sqrt{2y^2-5y}-\sqrt{21-6y}=0

asked by guest
on Nov 16, 2024 at 1:23 pm



You asked:

Solve the equation \(\sqrt{2 \cdot {y}^{2} - 5 y} - \sqrt{21 - 6 y} = 0\) for the variable \(y\).

MathBot Answer:

The 2 solutions to the equation are: \[\begin{aligned}y &= - \frac{7}{2} = -3.5\\y &= 3\end{aligned}\]