calculate the radius of a sphere with a volume of 4800
MathBot Answer:
The radius of a sphere is $\frac{2 \cdot \sqrt[3]{450}}{\sqrt[3]{\pi}} \approx 10.46\, \text{units}$.
Note: Approximate solutions are rounded to the nearest hundredths place.
Given: $$\begin{aligned}V&=4800\end{aligned}$$
Radius
The radius of a sphere is given by the equation: $$\begin{aligned}V&=\frac{4}{3} \pi r^{3}\end{aligned}$$ where $V$ is volume and $r$ is radius.
Solution:$$\begin{aligned}V&=\frac{4}{3} \pi r^{3}\\4800&=\frac{4}{3} \pi r^{3}\\r&=\frac{2 \cdot \sqrt[3]{450}}{\sqrt[3]{\pi}}\end{aligned}$$
A sphere is a three dimensional solid that has no flat surfaces, corners, or edges. Its radius r is the distance between the center of the sphere and any point on the surface of the sphere. Its diameter d is twice the radius, forming a line segment passing through the center of the sphere.
The circumference C of a sphere is the distance around the cross section containing the center of a sphere, i.e. the largest circular cross section of a sphere. $$\begin{aligned} C &= 2 \pi r \\ &= \pi d \end{aligned}$$
The surface area S of a sphere is the region occupied by its surface. $$S = 4 \pi r^{2}$$
The volume V of a sphere is the amount of space it occupies. $$V = \frac{4}{3} \pi r^{3}$$