2 $e^{2x}$ (2x-4) = 0

asked by guest
on Nov 28, 2024 at 11:39 am



You asked:

Investigate the equation: \(2 {e}^{2 x} \cdot \left(2 x - 4\right) = 0\).

MathBot Answer:

The solution is: \[x = 2\]

\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).

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