Solve for p.
p^2=80
You asked:
Solve the equation \[{p}^{2} = 80\] for the unknown \(p\).
MathBot Answer:
\[\begin{aligned}p &= 4 \sqrt{5} \approx 8.9442719\\p &= - 4 \sqrt{5} \approx -8.9442719\end{aligned}\]
Take the square root of both sides of the equation $$\begin{aligned}p^{2} &= 80 \\ \sqrt{p^{2}} &= \sqrt{80} \end{aligned}$$
Remember that both positive and negative numbers will result in a positive number when squared, so a square root will have both a positive and a negative answer. $$\begin{aligned}p &= \pm 4 \sqrt{5} \\ p = 4 \sqrt{5} &,\, p=-4 \sqrt{5}\end{aligned}$$