(x+4)(x^2-5x+7)
asked by guest on Apr 02, 2025 at 10:06 pm
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MathBot Answer:
(x+4)(x2−5x+7)=(x+4)(x2−5x+7)\displaystyle \left(x + 4\right) \left({x}^{2} - 5 x + 7\right) = \left(x + 4\right) \left(x^{2} - 5 x + 7\right) (x+4)(x2−5x+7)=(x+4)(x2−5x+7)
(x+4)(x2−5x+7)=x3−x2−13x+28\left(x + 4\right) \left({x}^{2} - 5 x + 7\right) = x^{3} - x^{2} - 13 x + 28(x+4)(x2−5x+7)=x3−x2−13x+28