ln(x^2/1-x)=lnx+ln(2x/1+x)
You asked:
Solve the equation \(\ln\left( \frac{{x}^{2}}{1} - x \right) = \ln\left( x \right) + \ln\left( \frac{2 x}{1} + x \right)\) for the variable \(x\).
MathBot Answer:
The solution is: \[x = - \frac{1}{2} = -0.5\]