10x/(3x-2)-3
asked by guest on Jan 28, 2025 at 2:44 pm
You asked:
MathBot Answer:
10x3x−2−3=10x3x−2−3\displaystyle \frac{10 x}{3 x - 2} - 3 = \frac{10 x}{3 x - 2} - 3 3x−210x−3=3x−210x−3
10x3x−2−3=10x3x−2−3\frac{10 x}{3 x - 2} - 3 = \frac{10 x}{3 x - 2} - 33x−210x−3=3x−210x−3
10x3x−2−3=x+63x−2\frac{10 x}{3 x - 2} - 3 = \frac{x + 6}{3 x - 2}3x−210x−3=3x−2x+6