x=2 y^{y} solve for y

asked by guest
on Mar 15, 2025 at 1:00 pm



You asked:

Solve the equation x=2yx = {2}^{y} for the unknown yy.

MathBot Answer:

y=log⁡(x)log⁡(2)∧−∞<y∧y<∞y = \frac{\log{\left(x \right)}}{\log{\left(2 \right)}} \wedge -\infty < y \wedge y < \infty

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