Find the general solution of 4cos^2 theta = 1

asked by guest
on Oct 20, 2024 at 6:19 pm



You asked:

Solve the equation \(4 \cdot {\cos\left( θ \right)}^{2} = 1\) for the variable \(θ\).

MathBot Answer:

The real solutions are: \[\begin{aligned}θ &= \left\{\frac{2 \pi \left(2 + 3 n\right)}{3}\; \middle|\; n \in \mathbb{Z}\right\} \approx \left\{6.2831853 n + 4.1887902\; \middle|\; n \in \mathbb{Z}\right\}\\θ &= \left\{\frac{2 \pi \left(1 + 3 n\right)}{3}\; \middle|\; n \in \mathbb{Z}\right\} \approx \left\{6.2831853 n + 2.0943951\; \middle|\; n \in \mathbb{Z}\right\}\\θ &= \left\{\frac{\pi \left(5 + 6 n\right)}{3}\; \middle|\; n \in \mathbb{Z}\right\} \approx \left\{6.2831853 n + 5.2359878\; \middle|\; n \in \mathbb{Z}\right\}\\θ &= \left\{\frac{\pi \left(1 + 6 n\right)}{3}\; \middle|\; n \in \mathbb{Z}\right\} \approx \left\{6.2831853 n + 1.0471976\; \middle|\; n \in \mathbb{Z}\right\}\end{aligned}\]

+ Submit Question