(4x-5)^2
asked by guest on Mar 17, 2025 at 5:36 am
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MathBot Answer:
(4x−5)2=(4x−5)2\displaystyle {\left( 4 x - 5 \right)}^{2} = \left(4 x - 5\right)^{2} (4x−5)2=(4x−5)2
(4x−5)2=16x2−40x+25{\left( 4 x - 5 \right)}^{2} = 16 x^{2} - 40 x + 25(4x−5)2=16x2−40x+25