2³+6÷(3+1)

asked by guest
on Jan 30, 2025 at 12:54 am



You asked:

Evaluate the expression: 23+63+1{2}^{3} + \frac{6}{3 + 1}

MathBot Answer:

23+63+1=192=9.5{2}^{3} + \frac{6}{3 + 1} = \frac{19}{2} = 9.5


23+63+1=23+613+1=8+613+1=8+64=8+32=192\begin{aligned}{2}^{3} + \frac{6}{3 + 1}& = 2^{3} + 6 \cdot \frac{1}{3 + 1}\\& = 8 + 6 \cdot \frac{1}{3 + 1}\\& = 8 + \frac{6}{4}\\& = 8 + \frac{3}{2}\\& = \frac{19}{2}\end{aligned}