341000−22z3\frac{341000-22z}{3} + 8.5z = 141000

asked by guest
on Mar 21, 2025 at 4:40 am



You asked:

Solve the equation 341000−22z3+8.5z=141000\frac{341000 - 22 z}{3} + 8.5 z = 141000 for the variable zz.

MathBot Answer:

The solution is: z=1640007=23428.571428‾z = \frac{164000}{7} = 23428.\overline{571428}

76z+3410003=14100076z=820003z=1640007\begin{aligned}\frac{7}{6} z + \frac{341000}{3} &= 141000\\\frac{7}{6} z &= \frac{82000}{3}\\z &= \frac{164000}{7}\end{aligned}

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