∫1102624x2+x+1dx\int_{1}^{10}{\frac{2624}{{x}^{2} + x + 1}}dx

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on Jan 22, 2025 at 10:08 am



You asked:

Evaluate the integral: ∫1102624x2+x+1dx\int_{1}^{10}{\frac{2624}{{x}^{2} + x + 1}}dx

MathBot Answer:

Definite integral

∫1102624x2+x+1dx=−5248π39+52483arctan⁡(73)3≈1337.12945768727539028547237373335125\int_{1}^{10}{\frac{2624}{{x}^{2} + x + 1}}dx = - \frac{5248 \pi \sqrt{3}}{9} + \frac{5248 \sqrt{3} \arctan{\left(7 \sqrt{3} \right)}}{3} \approx 1337.12945768727539028547237373335125

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