$x^{2}$ * $e^{-x}$- $e^{-x}$ = 0
You asked:
Investigate the equation: \({x}^{2} \cdot {e}^{-x} - {e}^{-x} = 0\).
MathBot Answer:
The 2 solutions to the equation are: \[\begin{aligned}x &= -1\\x &= 1\end{aligned}\]
\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).