1/x * sen^2 x + ln * 2 sen x cos x

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on Nov 25, 2024 at 10:44 am



You asked:

Evaluate the expression: 1xsin⁡(x)2+ln⋅2sin⁡(x)cos⁡(x)\frac{1}{x} {\sin\left( x \right)}^{2} + l n \cdot 2 \sin\left( x \right) \cos\left( x \right)

MathBot Answer:

Evaluated



1xsin⁡(x)2+ln⋅2sin⁡(x)cos⁡(x)=2lnsin⁡(x)cos⁡(x)+sin⁡2(x)x\displaystyle \frac{1}{x} {\sin\left( x \right)}^{2} + l n \cdot 2 \sin\left( x \right) \cos\left( x \right) = 2 l n \sin{\left(x \right)} \cos{\left(x \right)} + \frac{\sin^{2}{\left(x \right)}}{x}

Factored

1xsin⁡(x)2+ln⋅2sin⁡(x)cos⁡(x)=(2lnxcos⁡(x)+sin⁡(x))sin⁡(x)x\frac{1}{x} {\sin\left( x \right)}^{2} + l n \cdot 2 \sin\left( x \right) \cos\left( x \right) = \frac{\left(2 l n x \cos{\left(x \right)} + \sin{\left(x \right)}\right) \sin{\left(x \right)}}{x}

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