Math Problem Solver

$$9 + 8 + 4.5 + 8 + 23 + 12 + 5 + 5 + 3 - 3 = \frac{149}{2} = 74.5$$

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of $\frac{9}{1}$, $\frac{8}{1}$, $\frac{4}{1}$, $\frac{5}{10}$, $\frac{8}{1}$, $\frac{23}{1}$, $\frac{12}{1}$, $\frac{5}{1}$, $\frac{5}{1}$, $\frac{3}{1}$, and $\frac{-3}{1}$ is $10$. $$\begin{aligned} 9 + 8 + 4.5 + 8 + 23 + 12 + 5 + 5 + 3 - 3 &= \frac{9 \cdot 10}{1 \cdot 10} + \frac{8 \cdot 10}{1 \cdot 10} + \frac{4 \cdot 10}{1 \cdot 10} + \frac{5 \cdot 1}{10 \cdot 1} + \frac{8 \cdot 10}{1 \cdot 10} + \frac{23 \cdot 10}{1 \cdot 10} + \frac{12 \cdot 10}{1 \cdot 10} + \frac{5 \cdot 10}{1 \cdot 10} + \frac{5 \cdot 10}{1 \cdot 10} + \frac{3 \cdot 10}{1 \cdot 10} + \frac{-3 \cdot 10}{1 \cdot 10} \\ &= \frac{90 + 80 + 40 + 5 + 80 + 230 + 120 + 50 + 50 + 30 + -30}{10} \\ &= \frac{745}{10} \\&= \frac{149}{2} \end{aligned}$$