Solve for x:

x^4-x^2+y^2*pi^2-2*y*pi*arccos(x)+arccos^2(x)=0

asked by guest
on Mar 29, 2025 at 5:12 pm



You asked:

Solve the equation x4x2+y2π22yπarccos(x)+arccos(x)2=0{x}^{4} - {x}^{2} + {y}^{2} {\pi}^{2} - 2 y \pi \arccos\left( x \right) + {\arccos\left( x \right)}^{2} = 0 for the unknown xx.