p=32e^-.04q
You asked:
Investigate the equation: \(p = 32 \cdot {e}^{-.04} \cdot q\).
MathBot Answer:
The graph of \(p = 32 \cdot {e}^{-.04} \cdot q\) is a line.
The p-intercept is \(0\).
The q-intercept is \(0\).
The slope of the line is \(\frac{e^{\frac{1}{25}}}{32}\).
The slope-intercept form of the line is \(q = p \frac{e^{\frac{1}{25}}}{32} + 0\).
The line in standard form is \( 1 p + q \left(- \frac{32}{e^{\frac{1}{25}}}\right) + 0 = 0 \)
\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).