(1/2x^-1/2y^1/2)/(1/2x^1/2y^-1/2)

asked by guest
on Jan 22, 2025 at 4:03 am



You asked:

Evaluate the expression: \(\frac{\frac{\frac{\frac{1}{2 {x}^{-1}}}{2 {y}^{1}}}{2}}{\frac{\frac{\frac{1}{2 {x}^{1}}}{2 {y}^{-1}}}{2}}\)

MathBot Answer:

\[\frac{\frac{\frac{\frac{1}{2 {x}^{-1}}}{2 {y}^{1}}}{2}}{\frac{\frac{\frac{1}{2 {x}^{1}}}{2 {y}^{-1}}}{2}} = \frac{x^{2}}{y^{2}}\]