x^-x-8=0

asked by guest
on Nov 25, 2024 at 4:41 am



You asked:

Solve the equation \({x}^{-x} - 8 = 0\) for the variable \(x\).

MathBot Answer:

The complex solutions are: \[\left\{x\; \middle|\; x \in \mathbb{R} \wedge x^{x} - \frac{1}{8} = 0 \right\} \setminus \left\{x\; \middle|\; x \in \mathbb{R} \wedge x^{x} = 0 \right\}\]

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