Math Problem Solver

\[ 2\frac{1}{3} + 3\frac{1}{4} - \frac{1}{12} = \frac{11}{2} = 5.5 \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{2}{1}\), \(\frac{1}{3}\), \(\frac{3}{1}\), \(\frac{1}{4}\), and \(\frac{-1}{12}\) is \(12\). \[ \begin{aligned} 2\frac{1}{3} + 3\frac{1}{4} - \frac{1}{12} &= \frac{2 \cdot 12}{1 \cdot 12} + \frac{1 \cdot 4}{3 \cdot 4} + \frac{3 \cdot 12}{1 \cdot 12} + \frac{1 \cdot 3}{4 \cdot 3} + \frac{-1 \cdot 1}{12 \cdot 1} \\ &= \frac{24 + 4 + 36 + 3 + -1}{12} \\ &= \frac{66}{12} \\&= \frac{11}{2} \end{aligned} \]