h(x)=
1−(α
−exp(−ηx)
)
θ
(α
−exp(−ηx)
)
θ
⋅θ⋅η⋅exp(−ηx)⋅ln(α)
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
h(x)=
1−(α
−exp(−ηx)
)
θ
(α
−exp(−ηx)
)
θ
⋅θ⋅η⋅exp(−ηx)⋅ln(α)
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.