if s=3i-j and t=2i+3j find (t+35)
asked by guest on Jan 25, 2025 at 6:02 pm
MathBot Answer:
t+35=3j+35+2it + 35 = 3 j + 35 + 2 it+35=3j+35+2i
t+35=t+35=35+3j+2i=3j+2i+35=3j+35+2i\begin{aligned}t + 35&=t + 35\\&=35 + 3 j + 2 i\\&=3 j + 2 i + 35\\&=3 j + 35 + 2 i\end{aligned}t+35=t+35=35+3j+2i=3j+2i+35=3j+35+2i
iii is the imaginary unit, defined as i2=−1i^2 = -1i2=−1.
