Math Problem Solver

$$5501 - 789=4712$$

$$\begin{aligned} \overset{\mathtt{{\scriptscriptstyle 4}}}{\cancel{\mathtt{5}}}\overset{\mathtt{{\scriptscriptstyle 14}}}{\cancel{\mathtt{5}}}\overset{\mathtt{{\scriptscriptstyle 9}}}{\cancel{\mathtt{0}}}\overset{\mathtt{{\scriptscriptstyle 11}}}{\cancel{\mathtt{1}}}\\ \mathtt{-\phantom{0}}\phantom{0}\mathtt{7}\mathtt{8}\mathtt{9}\\ \hline \mathtt{4}\mathtt{7}\mathtt{1}\mathtt{2} \end{aligned}$$

Borrow $10^{2}$, resulting in $4$ in the $10^{2}$ place, and $10$ in the $10^{1}$ place.

Borrow $10^{1}$, resulting in $9$ in the $10^{1}$ place, and $11$ in the $10^{0}$ place.

$2$ is the digit in the $10^{0}$ place. $11 \times 10^{0} - 9 \times 10^{0} = 2 \times 10^{0}$.

$1$ is the digit in the $10^{1}$ place. $9 \times 10^{1} - 8 \times 10^{1} = 1 \times 10^{1}$.

Borrow $10^{3}$, resulting in $4$ in the $10^{3}$ place, and $14$ in the $10^{2}$ place.

$7$ is the digit in the $10^{2}$ place. $14 \times 10^{2} - 7 \times 10^{2} = 7 \times 10^{2}$.

$4$ is the digit in the $10^{3}$ place. $4 \times 10^{3} - 0 \times 10^{3} = 4 \times 10^{3}$.