for sequences, u(n)=n/2^n
find u(n+1)
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
for sequences, u(n)=n/2^n
find u(n+1)
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.