3/2×10/h'
asked by guest on Nov 14, 2024 at 8:37 am
You asked:
MathBot Answer:
32⋅10h′=15ddth(t)\frac{\frac{3}{2} \cdot 10}{h^{\prime}} = \frac{15}{\frac{d}{d t} h{\left(t \right)}}h′23⋅10=dtdh(t)15