0.56 = 247 / 247 + FN

asked by guest
on Mar 22, 2025 at 3:35 am



You asked:

Investigate the equation: 0.56=247247+FN0.56 = \frac{247}{247} + F N.

MathBot Answer:

The graph of the equation 0.56=247247+FN0.56 = \frac{247}{247} + F N is a hyperbola.


The coordinates of its foci are: (225,225)\left(- \frac{\sqrt{22}}{5}, \frac{\sqrt{22}}{5}\right) and (225,225)\left(\frac{\sqrt{22}}{5}, - \frac{\sqrt{22}}{5}\right).

The coordinates of its vertices are: (115,115)\left(- \frac{\sqrt{11}}{5}, \frac{\sqrt{11}}{5}\right) and (115,115)\left(\frac{\sqrt{11}}{5}, - \frac{\sqrt{11}}{5}\right).

The asymptotes have equations: 411N=04 \sqrt{11} N = 0 and 411F=0- 4 \sqrt{11} F = 0.

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