7p*1/2x^2/p/4-7x

asked by guest
on Jan 19, 2025 at 8:50 am



You asked:

Evaluate the expression: \(\frac{\frac{\frac{7 p \cdot 1}{2 {x}^{2}}}{p}}{4} - 7 x\)

MathBot Answer:

Evaluated



\(\displaystyle \frac{\frac{\frac{7 p \cdot 1}{2 {x}^{2}}}{p}}{4} - 7 x = - 7 x + \frac{7}{8 x^{2}} \)

Factored

\[\frac{\frac{\frac{7 p \cdot 1}{2 {x}^{2}}}{p}}{4} - 7 x = - \frac{7 \cdot \left(2 x - 1\right) \left(4 x^{2} + 2 x + 1\right)}{8 x^{2}}\]

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