f(x+3)=x^2+4 then what is f(x)

asked by guest
on Jan 09, 2025 at 10:18 am



MathBot Answer:

f(x)∈{f(f2−f2+12f−162),f(f2+f2+12f−162)}f{\left(x \right)} \in \left\{f{\left(\frac{f}{2} - \frac{\sqrt{f^{2} + 12 f - 16}}{2} \right)}, f{\left(\frac{f}{2} + \frac{\sqrt{f^{2} + 12 f - 16}}{2} \right)}\right\}

+ Submit Question