z^6-54iz^3-729=0

asked by guest
on Nov 15, 2024 at 11:33 pm



You asked:

Investigate the equation: \({z}^{6} - 54 i \cdot {z}^{3} - 729 = 0\).

MathBot Answer:

The 3 solutions to the equation are: \[\begin{aligned}z &= -3 i\\z &= - \frac{3 \sqrt{3}}{2} + \frac{3 i}{2} \approx -2.5980762 + 1.5 i\\z &= \frac{3 \sqrt{3}}{2} + \frac{3 i}{2} \approx 2.5980762 + 1.5 i\end{aligned}\]


\(i\) is the imaginary unit, defined as \(i^2 = -1\).