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Solution of dy/dx = x²y(x²+4)²/xy²-xy³
asked by
guest
on Mar 13, 2025 at 12:18 am
You asked:
Investigate the equation:
d
y
d
x
=
x
2
y
(
x
2
+
4
)
2
x
y
2
−
x
y
3
\frac{d y}{d x} = \frac{{x}^{2} {y\left( {x}^{2} + 4 \right)}^{2}}{x {y}^{2}} - x {y}^{3}
d
x
d
y
=
x
y
2
x
2
y
(
x
2
+
4
)
2
−
x
y
3
.
+ Submit Question
