integrate 8 cos t cos 2t

asked by guest
on Jan 29, 2025 at 2:02 am



You asked:

Evaluate the integral: 8cos(t)cos(2t)dt\int{8 \cos\left( t \right) \cos\left( 2 t \right)}dt

MathBot Answer:

Antiderivative

8cos(t)cos(2t)dt=8cos(2t)sin(t)3+16cos(t)sin(2t)3+C\int{8 \cos\left( t \right) \cos\left( 2 t \right)}dt = - \frac{8 \cos{\left(2 t \right)} \sin{\left(t \right)}}{3} + \frac{16 \cos{\left(t \right)} \sin{\left(2 t \right)}}{3} + C