Without expansion, prove:
∣
1
/
𝑎
𝑏
/
𝑎
𝑏
+
𝑐
1
/
𝑏
𝑐
/
𝑏
𝑐
+
𝑑
1
/
𝑐
𝑑
/
𝑐
𝑑
+
𝑎
∣
=
0
1/a
1/b
1/c
b/a
c/b
d/c
b+c
c+d
d+a
=0
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
Without expansion, prove:
∣
1
/
𝑎
𝑏
/
𝑎
𝑏
+
𝑐
1
/
𝑏
𝑐
/
𝑏
𝑐
+
𝑑
1
/
𝑐
𝑑
/
𝑐
𝑑
+
𝑎
∣
=
0
1/a
1/b
1/c
b/a
c/b
d/c
b+c
c+d
d+a
=0
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.