g(x)=1/xsquared+2
domain and range
You asked:
Find the domain and the range of \(g\left( x \right) = \frac{1}{{x}^{2}} + 2\)
MathBot Answer:
The domain of \(g(x)=2 + \frac{1}{x^{2}}\) is \(\left(-\infty, 0\right) \cup \left(0, \infty\right)\).
The range of \(g(x)=2 + \frac{1}{x^{2}}\) is \(\left(2, \infty\right)\).