Math Problem Solver

\[ 3\frac{1}{4} + 4\frac{1}{12} = \frac{22}{3} = 7.\overline{3} \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{3}{1}\), \(\frac{1}{4}\), \(\frac{4}{1}\), and \(\frac{1}{12}\) is \(12\). \[ \begin{aligned} 3\frac{1}{4} + 4\frac{1}{12} &= \frac{3 \cdot 12}{1 \cdot 12} + \frac{1 \cdot 3}{4 \cdot 3} + \frac{4 \cdot 12}{1 \cdot 12} + \frac{1 \cdot 1}{12 \cdot 1} \\ &= \frac{36 + 3 + 48 + 1}{12} \\ &= \frac{88}{12} \\&= \frac{22}{3} \end{aligned} \]