lim sinx-1 / x-1

x->0

asked by guest
on Sep 22, 2024 at 8:16 am



You asked:

Evaluate the expression: \(\lim_{x \to 0}{\sin\left( x \right) - \frac{1}{x} - 1}\)

MathBot Answer:

The two-sided limit \(\lim_{x \to 0}{\sin\left( x \right) - \frac{1}{x} - 1}\) does not exist because the directional limits from the right and the left result in different values.


Right limit:
\(\displaystyle\lim_{x \to 0^+}\left(\sin{\left(x \right)} - 1 - \frac{1}{x}\right) = -\infty\)


Left limit:
\(\displaystyle\lim_{x \to 0^-}\left(\sin{\left(x \right)} - 1 - \frac{1}{x}\right) = \infty\)